Nm [9 0]
In the hydrogen spectrum, what is the wavelength of light associated with the n=2 to n=1 electron transition?
a)1.097 nm
b)364.9 nm
c)0.1097 x 10^-8 cm
d)9.122 x 10^-8 m
e) 1.216 x 10^-7 m
This problem is slightly challenging, but not hard;)
To solve this, first you have to find the energy, and to do this you need to use the formula:
[2.18*10^-18/n^2 final - 2.18*10^-18/n^2 initial
So in this case it would look something like this:
[ 2.18*10^-18 / 1 - 2.18*10^-18/4] = 1.635*10^-18
Now that is your energy.
Now you use the formula :
E = hc / lamdba Where:
E = Energy
h = Planck's constant which is 6.626*10^-34
c = Speed of light which is 3.00*10^8
Lambda = wavelength'
So in the question they are asking for wavelength, so yoy manipulate the formula so you are solving for lamdba. So you'd have:
Lambda = hc/e
Lamdba = (6.626*10^-34)(3.00*10^8) / 1.635*10^-18 = 1.22*10^-7
So your answer would be e) 1.216*10^-7
Hope that helped!!
 |
 FLASH 180 VERY FINE NM 90  US $79.00
|
 AQUAMAN 52 VERY FINE NM 90 US $90.06
|
 SUB MARINER 7 VERY FINE NM 90 US $58.46
|
 SUB MARINER 65 CGC 90 VF NM OFF WHITE PAGES US $23.70
|
 Booster Gold set 0 9 all strict NM High Grade 2007 US $37.00
|
 AMAZING SPIDERMAN 177 VF NM 90 MARVEL GREEN GOBLIN US $23.69
|
 AMAZING SPIDERMAN 184 VF NM 90 MARVEL COMICS US $17.37
|
 CAPTAIN AMERICA ANNUAL 4 VF NM 90 MARVEL MAGNETO US $33.17
|
 DAREDEVIL MARVEL VOL1 26 VF NM 90 HIGH GRADE US $63.20
|
 CGC GOLD KEY MIGHTY SAMSON 9 NM 94 0W 6009 1967 US $142.50
|